Question

calculate the mass of calcium phosphate obtained from 3 mol of calcium oxide and 1 mol of tetraphosphorus decaoxide​

Answer 1

Kindly refer the image

Answer 2

The mass of calcium phosphate obtained from 3 mol of calcium oxide and 1 mol of tetraphosphorus decaoxide is 310 grams.

Given:

3 mol of calcium oxide and 1 mol of tetraphosphorus decaoxide.

To Find:

The mass of calcium phosphate was obtained.

Solution:

To find the mass of calcium phosphate obtained we will follow the following steps:

As we know,

6CaO + P4O10 -------> 2Ca3(PO4)2

1 mol of P4O10 reacts with 6 moles of CaO. Then, 3 moles of CaO react with 0.5 moles of P4O10. so, CaO is the limiting reagent and CaO decides the product formation.

Now,

6 mole of CaO gives 2 moles of Ca3(PO4)2

3 mole of CaO will give 1 mole of Ca3(PO4)2.

So, the mass of 1 mole of Ca3(PO4)2 = 3 × 40 + 2 × (31 + 16 × 4) = 120+ 2× 95 = 120+ 190 =310 grams.

Henceforth, the mass of calcium phosphate obtained from 3 mol of calcium oxide and 1 mol of tetraphosphorus decaoxide is 310 grams.