Question

Calculate the mass of calcium reacting with 32 grams of oxygen to form 72 Kg of calcium oxide.

Answer 1

Explanation:

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The stoichiometric equation is...

Ca(s)+1 2O2(g)→CaO(g)

And so ONE equiv of metal reacts with an 1/2 EQUIV of dioxygen gas...

You got

72⋅g

calcium oxide, a molar quantity of

72⋅g 56.08⋅g⋅mol−1=1.28⋅mol

And SO WITH RESPECT TO OXYGEN there is a mass of ...

1.28⋅mol×16.00⋅g⋅mol−1=20.5⋅g

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Answer 2

Answer:

The stoichiometric equation is...

Ca(s)+1 2O2(g)→CaO(g)

And so ONE equiv of metal reacts with an 1/2 EQUIV of dioxygen gas...

You got

72⋅g

calcium oxide, a molar quantity of

72⋅g 56.08⋅g⋅mol−1=1.28⋅mol

And SO WITH RESPECT TO OXYGEN there is a mass of ...

1.28⋅mol×16.00⋅g⋅mol−1=20.5⋅g