calculate the mass of cane sugar in water required to prepare 200g of its 15 percent of mass it if the solution in water .
Answers
Answered by
67
The total mass of solution = 200 g
Mass of glucose ( cane sugar) = 15% of mass of solution = 15/100 x 200 = 30 g
Mass of water = 200 - 30 =170 g
Hope this answer is helpful to u.
Mass of glucose ( cane sugar) = 15% of mass of solution = 15/100 x 200 = 30 g
Mass of water = 200 - 30 =170 g
Hope this answer is helpful to u.
Answered by
3
Answer:
Explanation:
mass percentage = mass of solute* 100/ mass of solution
15 %=mass of suger *100/ 200
so, mass of suger = 15*200/100
= 30 g
mass of water =mass of solution + mass of suger
= 200+ 30
=230 g
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