Calculate the mass of carbon dioxide and water when 1 mole of glucose burns in excess air.
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Solution:
1 mole of carbon is burnt in air.
C+O
2
→CO
2
1 mole of C produces 1 mole of CO
2
which corresponds to 44 g of CO
2
.
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
16 g of dioxygen corresponds to
32
16
=0.5 moles.
Here, dioxygen is the limiting reagent.
It will produce 0.5 moles of CO
2
which corresponds to 0.5×44=22 g of CO2
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