Question

Calculate the mass of carbon dioxide formed when 10.6g of Sodium carbonate reacts with 7.3g of Hydrochloric acid to produce 11.7g of Sodium Chloride and 1.8g of water and Carbon dioxide.

Answer 1

Explanation:

Correct Question :-

10.6g of sodium carbonate reacted with 7.3g of hydrochloric acid producing 11.7 g of sodium chloride, 1.8 g of water and 4.4 g of carbon dioxide gas. show that this data varifies the law of conservation of mass

Required Answer :-

Mass of sodium carbonate = 10.6 g

Mass of Hydrochloric acid = 7.3 g

Mass of sodium chloride (produced) = 11.7 g

Mass of water (produced) = 1.8 g

Mass of carbondioxide gas (produced) = 4.4 g

The given chemical reaction is given by ,

$\begin{gathered}\cdot\sf \: Na_2CO_3 + 2HCl \longrightarrow 2NaCl + H_2 O + CO_2 \\ \\ \sf \: 10.6g + 7.3 \: g \: \: \: \: \: \: \: 11.7\:g + 1.8 \: g + 4.4 \: g\end{gathered}$

Law of conservation of mass states that the total mass of reactants should be equal to the total mass of products.

⇒ 10.6 g + 7.3 g = 11.7 g + 1.8 g + 4.4 g

⇒ 17.9 g = 17.9 g

Hence , The given data verfies the law of conservation of mass.