calculate the mass of carbon monoxide having same number of oxygen atoms as present in 88 grams of CO2.
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molecular mass of co is28
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then in CO2 the ratio of carbon and oxygen=
12:32=3:8. so the mass of oxygen=8/11×88=64 grams. then the no. of moles in O in CO2=64/16=4moles.then the mass CO=28×4=112 grams.
12:32=3:8. so the mass of oxygen=8/11×88=64 grams. then the no. of moles in O in CO2=64/16=4moles.then the mass CO=28×4=112 grams.
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