Question

Calculate the mass of carbon monoxide having same number of oxygen atoms as present in 4.4 grams of CO2.

Answer 1

Solution :

We know that ,

• Molar mass of CO2 = 44 g

• No of molecules of O present in 44 g or 1 mole of CO2 = 2 x 6.023 x 10²³

So ,

No of molecules of O present in 4.4 g  of CO2

= 2 x 6.023 x 10²³  x 4.4 / 44

= 6.023 x 10²³ / 5

= 1.2 x 10²³ atoms

As per the given data ,

• No of oxygen atoms in CO = 1.2 x 10²³ atoms

No of oxygen atoms in 1 mole or 28 g of CO = 6.023 x 10²³ atoms

Then ,

⇒ Mass of carbon monoxide = 1.2 x 10²³ x 28 / 6.023 x 10²³

⇒ Mass of carbon monoxide = 0.2 x 28

⇒ Mass of carbon monoxide = 5.6 g

5.6 g of carbon monoxide has same number of oxygen atoms as present in 4.4 grams of CO2 .