calculate the mass of carbon monoxide having same number of oxygen atoms as present in 32 grams of CO 2.
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Wt of o2 in co2= wt of o2 in CO
44grams of Co2 ----> 2 atoms of O
= 2* 6.023*10^23 atoms of O
Therefore,
22grms of Co2 has--> 1.45* NA(NA =Avogadro no.)
Thus wt of CO is =12+16*1.45
=35.2grams
44grams of Co2 ----> 2 atoms of O
= 2* 6.023*10^23 atoms of O
Therefore,
22grms of Co2 has--> 1.45* NA(NA =Avogadro no.)
Thus wt of CO is =12+16*1.45
=35.2grams
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