Chemistry, asked by basantakhatiwada21, 5 months ago

Calculate the mass of carbon monoxide having the same number of oxygen atoms as are

present in 88 gm of carbon dioxide.

Answers

Answered by cb299797

1

Answer:

4×6.022×1023 oxygen atoms are present in

CO=28.0×4×6.022×10236.022×1013=112.0g

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