Question

Calculate the mass of carbon monoxide having the
same number of oxygen atoms as are present in 88g of
carbon dioxide. ​

Answer 1

Answer:

The answer is 112g. The explanation is given below. Thank You.

Explanation:

$CO_{2}$ has mass molar mass = 44g (Molar mass of Oxygen atom = 16g)

(Molar Mass of Carbon atom = 12g) (44 = (16)(2) + 12 )

Number of moles of Carbon Dioxide in 88g = 2 (88/44 = 2)

(number of moles = given mass / molar mass)

One molecule of $CO_{2}$ contains 2 oxygen atoms

One mole Carbon Dioxide contains 2 moles of Oxygen atoms.

Two moles of Carbon Dioxide contains 4 moles of Oxygen

Now CO = formula for Carbon Monoxide

One mole of carbon monoxide contains one-mole oxygen atoms

Thus four moles of Carbon Monoxide contains 4 moles of oxygen atoms

We require the mass of 4 mole of Carbon monoxide

Mass of one mole pf carbon monoxide = (16+12) = 28g

ANSWER = 28 x 4 = 112g