Calculate the mass of carbon monoxide having the same number of oxygen atoms as are present in 88g of carbondioxide
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Answer:
112 g
Explanation:
No of oxygen atoms in CO2 = 2× 88/44 × Avogadro's constant
no of oxygen atoms = weight of CO/28 × Avogadro's constant
no of oxygen atoms in CO2 = no of oxygen atoms in CO
2× 88/44 = weight of CO/28
weight of CO = 112 g
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