Question

calculate the mass of CH3COONA required to make 500ml of 0.375molar aqueous solution. Given molar mass of CH3COONA=82mol​

Answer 1

Answer:

here's your answer dude

Answer 2

Answer:

Molarity = $\frac{Moles}{Voume(L)}$

       

0.375 = $\frac{Moles}{0.5L}$

∴ Moles = 0.1875

Moles = $\frac{Mass}{82}$

= Moles × Molar mass = Given Mass

= 0.1875 × 82

∴ Given mass = 15.375 grams