Hindi, asked by karan130904, 9 months ago

calculate the mass of CO in grams containing exactly the same number of O-atoms as present 22 gram of CO2

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Answered by khushal12349

$\huge\red{Answer!}$

22 g of CO2 = (22 x 2 x 6.023 x 1023)/44 = 6.023 x 1023 atoms of O. Now, 1 mole of CO = 6.023 x 1023 atoms of O. Therefore. 28g of CO = 6.023 x 1023 atoms of O

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calculate the mass of CO in grams containing exactly the same number of O-atoms as present 22 gram of CO2​

Answers

calculate the mass of CO in grams containing exactly the same number of O-atoms as present 22 gram of CO2