Question

calculate the mass of copper required to react 63g of dilute nitric acid.​

Answer 1

Answer:

1 gm of HNO3 reacts with (192 ÷ 504) = 0.381gm of Cu. So, 63 gm of HNO3 reacts with (0.381 × 63) = 24gm of Cu. (a) Mass of copper needed to react with 63 g of HNO3 is 24gm of Cu.......

Explanation:

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