Calculate the mass of copper required to react 63g of dilute nitric acid.
[ Cu= 64, H= 1, N=14, O=16]
Answers
Answered by
0
Answer:
sorry
Explanation:
calculated but cant find the answer.
Answered by
1
Answer:
☺️❤️
Explanation:
3Cu+8HNO
3
→3Cu(NO
3
)
2
+4H
2
O+2NO
Moles of nitric acid=
63
63
=1
3 moles of copper reacts with 8 moles of nitric acid therefore 1 mole of nitric acid reacts with three-eighth mole of copper.
Therefore, mass of copper=
8
3
×63.5=24 g☺️
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