Calculate the mass of Copper which could be obtained by the complete reaction of 5g Copper 2 oxide with excess hydrogen.
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3.99 grams is the mass of the copper which would be obtained by the complete reaction of 5 grams of Copper (II) oxide with excess of hydrogen.
Given-
- Weight of Copper (II) oxide = 5 grams
Reaction is as follows-
CuO + H₂ → Cu + H₂O
1 mol 1 mol
1×79.54g 1×63.54g
Here H₂ is in excess therefore CuO is the limiting reagent so it will be fully consumed.
79.54 gram of CuO gives 63.54 gram of Cu.
Therefore 5 gram of CuO will give
= 63.54/79.54 × 5 = 3.99 gram of Cu
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