Question

calculate the mass of CuSO4.5H2O required to prepare 500 cm3 of a 0.400 m/dm-3 solution

Answer 1

1000cm³=1L
500cm³=0.5L
1dm³=1L
molarity=mole/litre=0.4M
no.of moles=molarity*volume in L=0.4*0.5=0.2
No.of moles=mass/molecular mass
mass=0.2*159=31.8g