Calculate the mass of diphosphorus pentoxide (P2O5) that contains a trillion (1.000 x 10 ^ 12)oxygen atoms.
Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.
Answers
Calculate the mass of diphosphorus pentoxide (P2O5) that contains a trillion oxygen atoms.
solution : no of oxygen atoms = 10¹²
no of moles of oxygen atoms = no of oxygen atoms/Avogadro's number
= 10¹²/(6.023 × 10²³)
= 1.66 × 10¯¹² mol
we see, one mole of diphosphorus pentoxide contains 5 mole of oxygen atoms.
so, no of moles of diphosphorus pentoxide when no of moles of oxygen atoms is 1.66 × 10¯¹² = 1.66/5 × 10¯¹² = 0.332 × 10¯¹² mol
molecular mass of diphosphorus pentoxide = 283.886 g/mol
so mass of diphosphorus pentoxide = no of moles × molar mass
= 0.332 × 10¯¹² × 283.886
= 94.25 × 10¯¹² g
Therefore the mass of diphosphorus pentoxide is 94.25 × 10¯¹² g [ in four significant digits ]
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Calculate the mass of diphosphorus pentoxide (P2O5) that contains a trillion oxygen atoms.
solution : no of oxygen atoms = 10¹²
no of moles of oxygen atoms = no of oxygen atoms/Avogadro's number
= 10¹²/(6.023 × 10²³)
= 1.66 × 10¯¹² mol
we see, one mole of diphosphorus pentoxide contains 5 mole of oxygen atoms.
so, no of moles of diphosphorus pentoxide when no of moles of oxygen atoms is 1.66 × 10¯¹² = 1.66/5 × 10¯¹² = 0.332 × 10¯¹² mol
molecular mass of diphosphorus pentoxide = 283.886 g/mol
so mass of diphosphorus pentoxide = no of moles × molar mass
= 0.332 × 10¯¹² × 283.886
= 94.25 × 10¯¹² g
Therefore the mass of diphosphorus pentoxide is 94.25 × 10¯¹² g [ in four significant digits ]
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