Question

Calculate the mass of displaced water when a piece of 30 cm thick iceberg with surface area 1000 cm2 floats on water. Density of ice is 0.9 g/cm3.

Answer 1

Given:

A piece of 30 cm thick iceberg with surface area 1000 cm² floats on water. Density of ice is 0.9 g/cm³.

To find:

Mass of displaced water ?

Calculation:

During floating, the weight of iceberg is equal and opposite to the buoyant force provided by water.

$\sf \therefore \: weight = buoyant \: force$

$\sf \implies \: mg = f$

$\sf \implies \: V_{total} \times \sigma\times g = V_{in} \times \rho \times g$

$\sf \implies \:(30 \times 1000)\times 0.9 = V_{in} \times 1$

$\sf \implies \:(30 \times 1000)\times 0.9 = V_{in}$

$\sf \implies \:V_{in} = 30000 \times 0.9$

$\sf \implies \:V_{in} = 3000 \times 9$

$\sf \implies \:V_{in} = 27000 \: {cm}^{3}$

Now, this is volume of water displaced , so mass will be :

$\sf \implies \:mass = V_{in} \times \rho \\ \sf \implies \: mass = 27000 \times 1$

$\sf \implies \: mass = 27000 \: gm$

$\sf \implies \: mass = 27 \: kg$

So, mass of iceberg is 27 kg.

Answer 2

Answer:

27kg

Explanation:

27kg

m = 27000*1= 27000gm= 27 kg ans