Question

Calculate the mass of glucose in 900 ml of decimolar glucose solution ○ 34 gm 1.8 gm O 16.2 gm O O 68 gm​

Answer 1

Answer:

Given, Molarity =0.1 M; V=10 ml=0.01 litre

Number of moles =Molarity×volume (in liters)

=0.1×0.01

=10

−3

moles

Number of Molecules =moles×Avogadro number(N

A

)

=10

−3

×6.0×10

23

=6×10

20

molecules

So, the correct option is A

Explanation:

please mark me as brain list