Question

Calculate the mass of gold(III) chloride that contains a billion chlorine atoms.

Answer 1

Answer:

1 mole of AuCl3 weighs 303.33 grams and contains 6.022x10^24 molecules of AuCl3 and the same number of gold atoms. Therefore that is the question:

“if 303.33 g of AuCl3 contains 6.022x10^24 atoms of gold how many grams of golds will contain 1 billion (10^9) of gold atoms?” that means the following equation:

303.33 : 6.022x10^23 = X : 10^9 → X = 10^9 x 303.33 / 6.022x10^23 = 5.037 x 10^-13 grams