calculate the mass of H2 and O2 released at cathode and anode respectively by electrical decomposition of 36 gram of water.
Answers
formula of water H2O. molar mass of 1 H atom = 1g.
molar mass of 1 O atom= 16 g
molar mass of water molecule = (2 x 1) + 16= 18g.
now given mass of water = 36 g.
no of moles of water molecules = mass ÷molar mass.
= 36÷ 18 = 2 moles.
finally, H atoms accumulate at anode and O atoms at cathode.
no of moles of H atoms in 1 mole of H20
= 2 [as there are two atoms of hydrogen in 1 molecule of water]
so in 2 moles of water, 4 moles of H atoms will be present.
total mass of hydrogen gas= 4 x 1 = 4g.
similarly there are 2 moles of O atoms in 2 moles of water.
so total mass of oxygen gas =2 x 16 = 32 g.
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