Question

calculate the mass of H2SO4 present in 250 cm³ of seminormal solution​

Answer 1

Answer:

Explanation:

Semi normal means 0.5 N

So, 250 cm³ 0.5 N H2So4 has (250×0.5) ÷1000=0.125 equivalent H2So4.

1 equivalent H2So4 = 49 g

0.125 equivalent H2So4=49×0.125=6.125 g H2So4

.... Hope it will help you..

Answer 2

6.125 gram of $H_2SO_4$ present in 250 cm³ of seminormal solution​

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}$

We are given:

Normality = 0.5 N

Given mass of $H_2SO_4$ = x g

Equivalent mass of $H_2SO_4$ = $\frac{\text{Molecular mass}}{\text{Basicity}}=\frac{98}{2}=49g/eq$

Volume of solution = 250 ml

Putting values in above equation, we get:

$0.5=\frac{x\times 1000}{49g/eq\times 250mL}\\x =6.125g$

Learn more about normality

https://brainly.in/question/9458928

https://brainly.in/question/5989938