Question

calculate the mass of HCl that will be needed to react with 125g of Al to produced aluminum chloride.​

Answer 1

Answer:

Explanation:

al+3hcl = alcl3 + (3/2)h2

apply poac for al

moles of al = moles of alcl3

moles of hcl = 3 moles alcl3

3 moles of al = moles of hcl

3*125/27 = w/36.5

w=101.389 gm