Calculate the mass of-
i) 1mole of FeSO4.7H2O (atomic mass of Fe=56)
ii) 0.6 moles of Calcium carbonate
iii) 1.8066 x 1023 atoms of Na
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Answer:
i) 1 mole of Fe = 56 g
1 mole of S. = 32 g
1 mole of O. = 16 g
1 mole of. H. = 1 g
1 MOLE OF FeSO4.7H2O = Fe+S+4*O+ 7*2*H +7*O
= 56 + 32+ (4*16) + (7*2*1)+(7*16)
=56+32+64+14+112
=278g
One mole of FeSO4.7H2O has 278g molecular wt
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