Question

Calculate the mass of ice that can be melted by 16800 J of heat . Latent heat of fusion of ice is 336 J/g ​

Answer 1

Answer:

sorry I don't know the answer hope you're well dear xd

Answer 2

Answer:

150g is ur ans

Explanation:

Heat extracted by ice at 0

o

C to melt = Heat given by water to reach 0

o

C from 40

o

C.

ML=mcθ

Where, θ = change in temperature of water

L = Specific Latent heat of ice

c = Specific heat capacity of water

M = Mass of ice required

m = mass of water

M×336=300×4.2×(40−0)

M=

336

300×4.2×40

=150g

∴ Ice required to lower the temperature of water =150g