Question

calculate the mass of iron in 10kg of iron ore which contains 80%of pure ferric oxide​

Answer 1

Answer:

80*1000/100=800

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Answer 2

Answer:

Ferric oxide e.g Fe3O4

in 10kg iron ore Fe3O4 contain 10x 80/100 = 8kg

now,

1mole of Fe3O4 contain 3 mole of Fe

now,

no of mole of Fe3O4=8000g/(56 x 3+16 x 4) = 8000/232 =34.5

so, no of mole of Fe =3 x 34.5

=103.5 mole

we know ,

mole =wt./molecular wt.

103.5 = wt/56

wt. =103.5 x 56 g =5796 g =5.796 kg (approx value)