Question

Calculate the mass of KClO3 required to liberated 55g of oxygen.​

Answer 1

Answer:

1.96g

O 2

Explanation:

We first need our balanced equation:

2 K C l O 3

→ 2 K C l + 3 O 2

Answer 2

Answer:

The balanced chemical reaction is as shown below.

0.1 equivalent of chlorine corresponds to 0.05 moles of chlorine.

10 g sample contains 0.05 mole of MnO

2

or 0.05×86.9×4.35 g MnO

2

The percentage purity of the sample =

10

4.35

×100=43.5%