Chemistry, asked by sohamshashank, 1 month ago

Calculate the mass of KMnO4 required to prepare 10 L of 0.02 M solution. Given atomic weights of K = 39 , Mn=55, O=16.

Answers

Answered by AmyMallick

1

Answer:

31.6g

Explanation:

Molarity = mole/volume(l)

0.02M = moles/10L

therefore moles = 0.2

mass of KMnO4 required = 0.2 × (39+55+64)

=0.2 × 158

=31.6g

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