calculate the mass of krypton in a 1.46 litre cylinder at 47.3 degree Celsius and 7.87 bar
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Explanation:
We use the old Ideal Gas equation...
#n=(PV)/(RT)=(2.99*atmxx2.74*L)/(0.0821*(L*atm)/(K*mol)*331.9*K)#
#=0.301*mol#...
And we know (how) that krypton has a molar mass of #83.8*g*mol^-1#...
And so we take the product...…..
#0.301*molxx83.8*g*mol^-1=??*g#
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