Question

Calculate the mass of magnesium (in grams) which will contain 2.4088×10^24 number of magnesium atoms. (Mg=24u).
Plz answer fast..​

Answer 1

Answer:-

96g

Explanation:-

Given:-

→ Atoms of magnesium = 2.4088×10²⁴

→ Atomic mass of magneisum = 24u

To find:-

→ Mass of magnesium.

Solution:-

∵ Atomic mass of magnesium is 24u.

∴ It's molar mass is 24g/mol

• Avogadro Number = 6.022×10²³

Firstly, let's calculate the number of moles in 2.4088×10²⁴ atoms of magnesium. For this we will apply the formula:-

No of moles :-

= No of atoms/Avogadro number

= 2.4088×10²⁴/6.022×10²³

= 0.4×10

= 4 moles

Hence, 4 moles are there.

_____________________________

Now, we will calculate the required mass of magnesium by :-

=> Mass = No of moles × Molar mass

=> Mass = 4 × 24

=> Mass = 96g

Thus, the required mass of magnesium in grams is 96g .

Answer 2

Answer:-

96g

Explanation:-

Given:-

→ Atoms of magnesium = 2.4088×10²⁴

→ Atomic mass of magneisum = 24u

To find:-

→ Mass of magnesium.

Solution:-

∵ Atomic mass of magnesium is 24u.

∴ It's molar mass is 24g/mol

• Avogadro Number = 6.022×10²³

Firstly, let's calculate the number of moles in 2.4088×10²⁴ atoms of magnesium. For this we will apply the formula:-

No of moles :-

= No of atoms/Avogadro number

= 2.4088×10²⁴/6.022×10²³

= 0.4×10

= 4 moles

Hence, 4 moles are there.

_____________________________

Now, we will calculate the required mass of magnesium by :-

=> Mass = No of moles × Molar mass

=> Mass = 4 × 24

=> Mass = 96g

Thus, the required mass of magnesium in grams is 96g .