Question

Calculate the mass of mg metal required to concume 2560 of co2 in the reaction
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Answer 1

Answer:

2Mg+O2→2MgO

The atomic masses of Mg and O are 24.3 g/mol and 16 g/mol respectively.

The molar mass of MgO=24.3+16=40.3g/mol

Several moles are the ratio of mass to molar/atomic mass.

48.6 g of Mg corresponds to

24.3

48.6

=2 moles

64 g of O2 corresponds to

2×16

64

= 2 moles

2 moles of Mg will react with 1 mole of O

to produce 2 moles of MgO.

Since 2 moles of O

2are present, O

2 is an excess reagent and Mg is limiting reagent.

2 moles of Mg will give 2 moles of MgO.

Mass of MgO =2×40.3=80.6g