Calculate the mass of mg metal required to consume 2560g of co2 in the reaction
2mg5 +co2-> 2mgo5+c5
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Answer:
279g of Mg
Explanation:
Xg of Mg--->2Mg5
2560g of CO2--->5CO2
X=2560*2*24*5/5*(12+(16*2))
X=614400/220
X=279g
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