Question

Calculate the mass of N2 havinng same number of N atoms as present in 34g of NH3

Answer 1

Answer:

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Explanation:

Mass of 1 mol or (6.022×10

23

molecules) of NH

3

=14+3×1=17 g

Number o f molecules in 34 g NH

3

=

17

34

×6.022×10

23

=12.044×10

23

Number of atoms present in 1 molecule of NH

3

=4

Number of atoms in 34 g NH

3

=4×12.044×10

23

≈48×10

23

option D is correct