Question

calculate the mass of Na2CO3 present in 250ml of 0.25M solution​

Answer 1

Answer:

See In the above image buddy

Answer 2

Answer:

molar mass of Na2CO3 = 23.5×2+12+16×3=107

molarity= no. Moles of solute/volume of solution in litre

0.25=M×1000/m× 250. (M- given mas

m- molar mass

M= 0.25×107×250/1000

M=6.68 and.