Calculate the mass of Na2CO3, which has same number of oxygen atom as present in 2.8 g CO.
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Answered by
1
Answer:
As per the question moles of Na2CO3 is 0.05 moles. Molecular mass of Na2CO3 is 46+12+48=106gram. 0.05 moles will have mass =0.05×106=5.3grams. Thanks.
Answered by
1
Hey friend!
Here is your answer;
Mass of CO = 2.8 g
Molar mass of CO = 12 + 16 = 28 u
Then, no. Of moles of CO = 2.8/28 = 0.1 mol
No. Of moles of Na2CO3 = 0.1 mol
Molar mass of Na2CO3 = 23 x 2 + 12 + 16 x 3
= 46 + 12 + 48
= 106 u
Then,
Mass of 0.1 mol Na2CO3 is 106 x 0.1 g
= 10.6 g
Answer: 10.6 g
I hope it helps you and please respond with a thanks if you appreciate my answer
Here is your answer;
Mass of CO = 2.8 g
Molar mass of CO = 12 + 16 = 28 u
Then, no. Of moles of CO = 2.8/28 = 0.1 mol
No. Of moles of Na2CO3 = 0.1 mol
Molar mass of Na2CO3 = 23 x 2 + 12 + 16 x 3
= 46 + 12 + 48
= 106 u
Then,
Mass of 0.1 mol Na2CO3 is 106 x 0.1 g
= 10.6 g
Answer: 10.6 g
I hope it helps you and please respond with a thanks if you appreciate my answer
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