Calculate the mass of na2co3 which will have the same number of molecules as are contained in 12.3gm of mgso4.7h2o
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Molecular mass of Mgso4.7H2o is 24+32+64+7(18)=246 grams.
No.of moles=12.3/246=0.05 moles.
As per the question moles of na2co3 is 0.05 moles.
Molecular mass of na2co3 is 46+12+48=106gram.
0.05 moles will have mass=0.05*106=5.3grams
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