Question

calculate the mass of NaCl dissolved in 37.2 gm of water to lower freezing point 2 assume NaCl complete dissociation kf = 1.86​

Answer 1

Explanation:

i = 2/1 = 2

nacl is sodium chloride

Freezing point of a solution is given by

ΔTf = i Kf Sw x 1000 / Ms x W

Where Kf for water is 1.86 K kg/mol

Molar mass of the solute is (nacl) is 58.5 g/mol

Mass of water W = 37.2 g

ΔTf = 2 K

Mass of solute Sw = to be calculated

So substituting the given values we get

2 = 2 x 1.86 x Sw x 1000 / 58.5 x 37.2

Sw = 1.17 g

Answer 2

Answer:

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