Question

Calculate the mass of nacl to be dissolved in 37.2 g of water to lower the freezing point by 2 celcius, assuming nacl undergoes complete dissociation

Answer 1

Given Calculate the mass of nacl to be dissolved in 37.2 g of water to lower the freezing point by 2 celcius, assuming nacl undergoes complete dissociation

Let i be after dissociation / before dissociation

 i = 2/1 = 2

nacl is sodium chloride

Freezing point of a solution is given by

   ΔTf = i Kf Sw x 1000 / Ms x W

Where Kf for water is 1.86 K kg/mol

        Molar mass of the solute is (nacl) is 58.5 g/mol

       Mass of water W = 37.2 g

    ΔTf = 2 K

Mass of solute Sw = to be calculated

So substituting the given values we get

 2 = 2 x 1.86 x Sw x 1000 / 58.5 x 37.2

 Sw = 1.17 g  

Answer 2

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Given Calculate the mass of nacl to be dissolved in 37.2 g of water to lower the freezing point by 2 celcius, assuming nacl undergoes complete dissociation

Let i be after dissociation / before dissociation

 i = 2/1 = 2

nacl is sodium chloride

Freezing point of a solution is given by

   ΔTf = i Kf Sw x 1000 / Ms x W

Where Kf for water is 1.86 K kg/mol

        Molar mass of the solute is (nacl) is 58.5 g/mol

       Mass of water W = 37.2 g

    ΔTf = 2 K

Mass of solute Sw = to be calculated

So substituting the given values we get

 2 = 2 x 1.86 x Sw x 1000 / 58.5 x 37.2

 Sw = 1.17 g  

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