Calculate the mass of NaOH needed to no
a solution with final mass 60g. The density
is 1.5g/cm². The molarity of solution = 2.20
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final mass=60g
density=1.5g/cm³
volume=mass/density
=60/1.5
=40cm³
therefore,
volume of solution= 40cm³= 40mL (1cm³=1mL)
molarity=2.20
molarity=moles of solute/volume of solution in L
=moles of solute*1000/volume of solution in mL
2.20=moles of solute*1000/40
moles of solute=(2.20*40)/1000
=0.088
solute=NaOH
molar mass of NaOH=40g
moles of solute=given gram mass/molar mass
0.088=given gram mass/40
given gram mass =0.088*40
=3.520g
therefore mass of NaOH needed=3.520g
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