Calculate the mass of naoh required to neutralise 1.1 g p4o6in water?
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Explanation:
"
Molar mass of
Product formed by is neutralised by 8 mol NaOH.
Given, dissolved 1.1 g in water.
Therefore, the Product formed by will be neutralised by NaOH
Hence, Molarity of NaOH solution is 0.1M
0.1 mol NaOH is present in 1 L solution.
Therefore
= 400 ml of NaOH solution
Thus, the volume of NaOH = 0.4 L = 400 ml"
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