Question

Calculate the mass of NH3 produced if 200g of di-nitrogen reacts with 100g of di-hydrogen

Answer 1

Answer:

n2 + 3H2 =2NH3. now ni.of moles of N2 is 200/ 28 =7.1 and that if H2 is 100/2=50 now taking mole / sc= 7.1 / 1= 7.1 and 50 / 3=16.6 nitrogen is limiting reagent that is 7.1= mole /sc of nh3 so moles of ammonia is 14.2 now mass of ammonia formed will be 14.2 × 17=241.4