Question

calculate the mass of nitric oxide gas which occupy 5.6 litre at STp​

Answer 1

Answer:

mark me brailist

Explanation:

At S.T.P. 1 mole of a gas occupies a volume of 22.4 liters. Its mass will be equal to its molar mass.

The weight of 5.6 liters of a gas at S.T.P is 11 grams.

The weight of 22.4 litres of a gas at S.T.P will be 44 grams,

11g×5.622.4=44g

The molar mass of nitrous oxide

(N2O) is 14+14+16=44g/mol.

Hence, the gas is  nitrous oxide

(N2O).

Note: The molecular weight of phosphine PH3, phosgene COCl2 and nitric oxide NO

are  34 g/mol, 99 g/mol and 30 g/mol respectively