calculate the mass of Nitrogen in 1000 kg of Urea CO (NH2)2
Answers
Answered by
110
Heya user ,
Here is your answer !!
Molar mass of urea
= 12 + 16 + 2 ( 14 + 2 )
= 28 + 2 × 16
= 28 + 32
= 60 .
Molar mass of nitrogen = 14 .
Amount of nitrogen present by mass in 60 g of urea = 28 g .
So , mass of Nitrogen in 1000 kg of Urea CO(NH2)2 is :--
= ( 28 / 60 ) × 1000 kg
= 466.67 kg ....... [ Ans ]
Hope it helps you !!
Here is your answer !!
Molar mass of urea
= 12 + 16 + 2 ( 14 + 2 )
= 28 + 2 × 16
= 28 + 32
= 60 .
Molar mass of nitrogen = 14 .
Amount of nitrogen present by mass in 60 g of urea = 28 g .
So , mass of Nitrogen in 1000 kg of Urea CO(NH2)2 is :--
= ( 28 / 60 ) × 1000 kg
= 466.67 kg ....... [ Ans ]
Hope it helps you !!
Answered by
6
Explanation:
(Co(NH2)2)
molar mass = 60gm
60gm urea have 28gm nitrogen so 1000 kg urea will have
28×1000/60 = 467kg nitrogen
hope it helps
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