Calculate the mass of non volatile solute with molar mads 40,which sould be dissolved in 114 g of octane to reduce vapour pressure to 80%
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Ps=80% of P0=0.80
Solute =W40gmol−1
Solvent (octane)=114g114gmol−1
(molar mass of C8H18=114gmol−1)
Now P0−PsP0=x2
∴P0−0.80P0P0=W40W40+1
Or 0.8W40=0.2
⇒W=10g
I hope its helpful to you
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