Question

calculate the mass of o2 required to produce 176g of co2 during the combustion of ethane

Answer 1

Answer:

Combustion of ethane

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

176g of CO₂ = 4 Moles of CO₂

4 Moles of CO₂ is produced when 7 moles are O₂ is present.

∴ Moles of O₂ = 7

∴Mass of 7 Moles of O₂ = 7 × 32 = 224

$Mass$ $of$ $O_{2}$ $required$ $is$ $224$ $grams.$