Calculate the mass of oxalic acid dihydrate (H2C2O4.2H2O) required to prepare 0.1M, 250 ml of its aqueous
solution.
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Answer: 3.15g
Explanation:
Molarity = no.of mol of solute/volume of solution in L
0.1 = no.of mol/(250/1000)L
No.of mol = 0.1/4= 0.025
Wt. =( 0.025mol)×(126g/mol)
= 3.15g
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