Question

Calculate the mass of oxalic acid dihydrate required to prepare 0.1m 250ml of its aqueous solution​

Answer 1

Answer:

3.15

Explanation:

molarity=no of moles of solute/ volume of solution

ie, 0.1 M=n÷0.25L

n= 0.025 mol

no of moles = given mass ÷molar mass

molar mass =126 g

0.025=m÷126

m=0.025×126

=3.15 g

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