Calculate the mass of oxygen atom present in 50 g of CaCO3?
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The molecular formula of CaCO3 is 40+12+(16)3= 100
Hence, we have 50/100= 0.5mol of CaCO3.
From the formula, we can see that in 1 mol of CaCO3, 3 mol of oxygen atoms are present.
Hence, in 0.5 mol, we have 1.5 mol of oxygen atoms.
ANS:- 1.5×12= 18 grams.
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Hence, we have 50/100= 0.5mol of CaCO3.
From the formula, we can see that in 1 mol of CaCO3, 3 mol of oxygen atoms are present.
Hence, in 0.5 mol, we have 1.5 mol of oxygen atoms.
ANS:- 1.5×12= 18 grams.
PLEASE MARK MY ANSWER AS A BRAINLIEST.
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