Question

calculate the mass of oxygen in 16g of so3

Answer 1

Answer:

Mass of so3 =80g

Total moles in 16 g so3 =1/5 (16/80)

total moles of oxygen in 1/5 moles of so3 = 3/5

mass of oxygen in 16g so3 = 3/5×16 =48/5 =9.6 g

Explanation:

Answer 2

Answer:

Mass of oxygen present in $16g$of $SO_{3}$ $= 9.6g$

Explanation:

• Given, Mass of oxygen $=16g$

• To find the mass of oxygen in $16g$ of $SO_{3}$.
• Using mole-concept,

The number of moles in a sample is given by the mass of a substance divided by the atomic/molar mass of the substance.

Number of moles =  Given the mass of substance / Molar-Mass of substance

Molar Mass of  $SO_{3} =$ Atomic-Mass of  $Sulphur(S)$  $*$  Number of atoms of                          Sulphur in  $SO_{3}$  $+$ Atomic-Mass of  $Oxygen (O_{2} )$ * Number of atoms of oxygen in $SO_{3}$

• Atomic mass of $Sulphur = 32$ an Atomic mass of $Oxygen = 16$

• Number of atoms of Sulphur in $SO_{3} = 1Atom$
• Number of atoms of Oxygen in $SO_{3} = 3Atoms$

          $= 32 *1 + 16*3$

           $=32+48$

           $=80g/mol$

• Using mole-concept,

$Moles(SO_{3}) = \frac{Given-Mass (SO_{3}) }{Molar-Mass (SO_{3} )}$

$Moles (SO_{3} ) = \frac{16}{80}$

$Moles (SO_{3} ) = \frac{1}{5}moles$

• Moles of oxygen in $SO_{3} =$ $3 * moles (SO_{3} )$

                                        $=3 * \frac{1}{5}moles$

                                     $=\frac{3}{5} moles (O_{2} )$

we know that,

$Moles(oxygen) = \frac{Given-Mass(O_{2} )}{Atomic -mass (O_{2} ) }$

$Mass(O_{2} ) = Moles(O_{2} ) * Atomic -mass (O_{2})$

$Mass(O_{2} ) = \frac{3}{5} * 16$

$Mass(O_{2} ) = \frac{48}{5}$

$Mass(O_{2} ) = 9.6grams$

Therefore, the mass of oxygen in $16g$ of $SO_{3}$ is $9.6grams.$

#SPJ2